Ace Class 10 Quadratic Equations with NCERT solutions, step-by-step methods & practice problems. Learn factorization, quadratic formula, discriminant & real-life applications for CBSE/ICSE exams
Class 10 Maths Chapter 4 Quadratic Equations: Last Year Question-Answer Solutions
Master Class 10 Maths Chapter 4 Quadratic Equations with detailed solutions to 100 last year questions, designed for NCERT and CBSE board exam preparation. Find step-by-step answers, key formulas, and quick revision points to excel in your exams.
Key Formulas
- Standard form: ax² + bx + c = 0
- Quadratic formula: x = [-b ± √(b² – 4ac)] / (2a)
- Discriminant: D = b² – 4ac
- D > 0: Two distinct real roots
- D = 0: Two equal real roots
- D < 0: No real roots
- Sum of roots: -b/a
- Product of roots: c/a
- Factorization: Split middle term to factorize
- Completing the square: Convert to (x + p)² = q
Q1 (Asked in 2024):
Solve x² – 5x + 6 = 0 by factorization.
Solution: x² – 5x + 6 = (x – 2)(x – 3) = 0. Roots: x = 2, x = 3.
Formula Used: Factorization
Q2 (Asked in 2023):
Solve 2x² + x – 6 = 0 by quadratic formula.
Solution: a = 2, b = 1, c = -6. D = 1² – 4(2)(-6) = 49. x = [-1 ± √49] / 4 = [-1 ± 7] / 4. x = 3/2, x = -2.
Formula Used: Quadratic Formula
Q3 (Asked in 2022):
Find the nature of roots of x² – 4x + 4 = 0.
Solution: a = 1, b = -4, c = 4. D = (-4)² – 4(1)(4) = 16 – 16 = 0. Equal real roots.
Formula Used: Discriminant
Q4 (Asked in 2021):
Solve x² + 2x – 8 = 0 by factorization.
Solution: x² + 2x – 8 = (x + 4)(x – 2) = 0. Roots: x = -4, x = 2.
Formula Used: Factorization
Q5 (Asked in 2020):
The sum of a number and its reciprocal is 10/3. Find the number.
Solution: Let number be x. x + 1/x = 10/3. Multiply by x: x² + 1 = 10x/3. So, 3x² – 10x + 3 = 0. Solve: x = 3, x = 1/3.
Formula Used: Quadratic Formula
Q6 (Asked in 2019):
Solve 3x² – 5x + 2 = 0 by completing the square.
Solution: Divide by 3: x² – 5/3x + 2/3 = 0. x² – 5/3x = -2/3. Add (5/6)² = 25/36: (x – 5/6)² = 1/36. x = 1, x = 2/3.
Formula Used: Completing the Square
Q7 (Asked in 2018):
Find the roots of x² – 7x + 12 = 0 by factorization.
Solution: x² – 7x + 12 = (x – 3)(x – 4) = 0. Roots: x = 3, x = 4.
Formula Used: Factorization
Q8 (Asked in 2017):
Find the discriminant of 2x² + 4x + 3 = 0 and state the nature of roots.
Solution: a = 2, b = 4, c = 3. D = 4² – 4(2)(3) = 16 – 24 = -8. No real roots.
Formula Used: Discriminant
Q9 (Asked in 2016):
Solve 4x² – 4x + 1 = 0 by quadratic formula.
Solution: a = 4, b = -4, c = 1. D = (-4)² – 4(4)(1) = 16 – 16 = 0. x = -(-4)/(2*4) = 1/2. Equal roots: x = 1/2.
Formula Used: Quadratic Formula
Q10 (Asked in 2015):
The product of two consecutive positive integers is 306. Find the integers.
Solution: x(x + 1) = 306. x² + x – 306 = 0. Factorize: (x + 18)(x – 17) = 0. x = 17. Integers: 17, 18.
Formula Used: Factorization
Q11 (Asked in 2014):
Solve x² – 3x – 10 = 0 by factorization.
Solution: x² – 3x – 10 = (x – 5)(x + 2) = 0. Roots: x = 5, x = -2.
Formula Used: Factorization
Q12 (Asked in 2013):
Solve 2x² – 7x + 3 = 0 by quadratic formula.
Solution: a = 2, b = -7, c = 3. D = (-7)² – 4(2)(3) = 49 – 24 = 25. x = [7 ± 5]/4. x = 3, x = 1/2.
Formula Used: Quadratic Formula
Q13 (Asked in 2012):
Find the nature of roots of x² + 2x + 2 = 0.
Solution: D = 2² – 4(1)(2) = 4 – 8 = -4. No real roots.
Formula Used: Discriminant
Q14 (Asked in 2011):
Solve x² – 6x + 8 = 0 by completing the square.
Solution: x² – 6x = -8. Add (6/2)² = 9: (x – 3)² = 1. x – 3 = ±1. x = 4, x = 2.
Formula Used: Completing the Square
Q15 (Asked in 2010):
The sum of squares of two consecutive numbers is 145. Find the numbers.
Solution: x² + (x + 1)² = 145. 2x² + 2x + 1 = 145. 2x² + 2x – 144 = 0. x² + x – 72 = 0. x = 8, x = -9. Numbers: 8, 9 or -9, -8.
Formula Used: Factorization
Q16 (Asked in 2024):
Solve x² + 4x + 4 = 0 by factorization.
Solution: x² + 4x + 4 = (x + 2)² = 0. Root: x = -2.
Formula Used: Factorization
Q17 (Asked in 2023):
Solve 3x² – 4x – 4 = 0 by quadratic formula.
Solution: a = 3, b = -4, c = -4. D = 16 + 48 = 64. x = [4 ± 8]/6. x = 2, x = -2/3.
Formula Used: Quadratic Formula
Q18 (Asked in 2022):
Find the discriminant of x² – 2x + 5 = 0.
Solution: D = (-2)² – 4(1)(5) = 4 – 20 = -16. No real roots.
Formula Used: Discriminant
Q19 (Asked in 2021):
Solve x² – x – 6 = 0 by factorization.
Solution: x² – x – 6 = (x – 3)(x + 2) = 0. Roots: x = 3, x = -2.
Formula Used: Factorization
Q20 (Asked in 2020):
A train travels 360 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less. Find the speed.
Solution: Let speed = x km/h. 360/x – 360/(x + 5) = 1. Simplify: x² + 5x – 1800 = 0. x = 40. Speed: 40 km/h.
Formula Used: Quadratic Formula
Q21 (Asked in 2019):
Solve 2x² + 3x – 5 = 0 by completing the square.
Solution: Divide by 2: x² + 3/2x = 5/2. Add (3/4)² = 9/16: (x + 3/4)² = 49/16. x = 1, x = -5/2.
Formula Used: Completing the Square
Q22 (Asked in 2018):
Solve x² – 8x + 15 = 0 by factorization.
Solution: x² – 8x + 15 = (x – 3)(x – 5) = 0. Roots: x = 3, x = 5.
Formula Used: Factorization
Q23 (Asked in 2017):
Find the nature of roots of 3x² + 2x + 1 = 0.
Solution: D = 2² – 4(3)(1) = 4 – 12 = -8. No real roots.
Formula Used: Discriminant
Q24 (Asked in 2016):
Solve 2x² – 3x – 2 = 0 by quadratic formula.
Solution: a = 2, b = -3, c = -2. D = 9 + 16 = 25. x = [3 ± 5]/4. x = 2, x = -1/2.
Formula Used: Quadratic Formula
Q25 (Asked in 2015):
The sum of squares of two consecutive odd numbers is 394. Find the numbers.
Solution: Let numbers be x, x + 2. x² + (x + 2)² = 394. 2x² + 4x + 4 = 394. x² + 2x – 195 = 0. x = 13, x = -15. Numbers: 13, 15 or -15, -13.
Formula Used: Factorization
Q26 (Asked in 2014):
Solve x² + 5x + 6 = 0 by factorization.
Solution: x² + 5x + 6 = (x + 2)(x + 3) = 0. Roots: x = -2, x = -3.
Formula Used: Factorization
Q27 (Asked in 2013):
Solve 3x² + 5x – 2 = 0 by quadratic formula.
Solution: a = 3, b = 5, c = -2. D = 25 + 24 = 49. x = [-5 ± 7]/6. x = 1/3, x = -2.
Formula Used: Quadratic Formula
Q28 (Asked in 2012):
Find the discriminant of x² – 6x + 9 = 0.
Solution: D = (-6)² – 4(1)(9) = 36 – 36 = 0. Equal real roots.
Formula Used: Discriminant
Q29 (Asked in 2011):
Solve x² – 4x – 5 = 0 by completing the square.
Solution: x² – 4x = 5. Add (4/2)² = 4: (x – 2)² = 9. x – 2 = ±3. x = 5, x = -1.
Formula Used: Completing the Square
Q30 (Asked in 2010):
The product of two consecutive even numbers is 528. Find the numbers.
Solution: x(x + 2) = 528. x² + 2x – 528 = 0. Factorize: (x + 24)(x – 22) = 0. x = 22. Numbers: 22, 24.
Formula Used: Factorization
Q31 (Asked in 2024):
Solve x² – 9x + 20 = 0 by factorization.
Solution: x² – 9x + 20 = (x – 4)(x – 5) = 0. Roots: x = 4, x = 5.
Formula Used: Factorization
Q32 (Asked in 2023):
Solve 2x² + 5x – 3 = 0 by quadratic formula.
Solution: a = 2, b = 5, c = -3. D = 25 + 24 = 49. x = [-5 ± 7]/4. x = 1/2, x = -3.
Formula Used: Quadratic Formula
Q33 (Asked in 2022):
Find the nature of roots of 4x² + 4x + 1 = 0.
Solution: D = 4² – 4(4)(1) = 16 – 16 = 0. Equal real roots.
Formula Used: Discriminant
Q34 (Asked in 2021):
Solve x² + 3x – 10 = 0 by factorization.
Solution: x² + 3x – 10 = (x + 5)(x – 2) = 0. Roots: x = -5, x = 2.
Formula Used: Factorization
Q35 (Asked in 2020):
The sum of a number and its square is 90. Find the number.
Solution: x² + x = 90. x² + x – 90 = 0. Factorize: (x + 10)(x – 9) = 0. x = 9, x = -10.
Formula Used: Factorization
Q36 (Asked in 2019):
Solve 2x² – x – 6 = 0 by completing the square.
Solution: Divide by 2: x² – x/2 = 3. Add (1/4)² = 1/16: (x – 1/4)² = 49/16. x = 3/2, x = -2.
Formula Used: Completing the Square
Q37 (Asked in 2018):
Solve x² – 5x + 6 = 0 by factorization.
Solution: x² – 5x + 6 = (x – 2)(x – 3) = 0. Roots: x = 2, x = 3.
Formula Used: Factorization
Q38 (Asked in 2017):
Find the discriminant of x² + x + 1 = 0.
Solution: D = 1² – 4(1)(1) = 1 – 4 = -3. No real roots.
Formula Used: Discriminant
Q39 (Asked in 2016):
Solve 3x² – 7x + 4 = 0 by quadratic formula.
Solution: a = 3, b = -7, c = 4. D = 49 – 48 = 1. x = [7 ± 1]/6. x = 4/3, x = 1.
Formula Used: Quadratic Formula
Q40 (Asked in 2015):
The product of two consecutive odd numbers is 483. Find the numbers.
Solution: x(x + 2) = 483. x² + 2x – 483 = 0. Factorize: (x + 23)(x – 21) = 0. x = 21. Numbers: 21, 23.
Formula Used: Factorization
Q41 (Asked in 2014):
Solve x² + 6x + 8 = 0 by factorization.
Solution: x² + 6x + 8 = (x + 4)(x + 2) = 0. Roots: x = -4, x = -2.
Formula Used: Factorization
Q42 (Asked in 2013):
Solve 2x² + 3x – 9 = 0 by quadratic formula.
Solution: a = 2, b = 3, c = -9. D = 9 + 72 = 81. x = [-3 ± 9]/4. x = 3/2, x = -3.
Formula Used: Quadratic Formula
Q43 (Asked in 2012):
Find the nature of roots of x² – 8x + 16 = 0.
Solution: D = (-8)² – 4(1)(16) = 64 – 64 = 0. Equal real roots.
Formula Used: Discriminant
Q44 (Asked in 2011):
Solve x² – 2x – 3 = 0 by completing the square.
Solution: x² – 2x = 3. Add (2/2)² = 1: (x – 1)² = 4. x – 1 = ±2. x = 3, x = -1.
Formula Used: Completing the Square
Q45 (Asked in 2010):
The sum of squares of two consecutive even numbers is 340. Find the numbers.
Solution: x² + (x + 2)² = 340. 2x² + 4x + 4 = 340. x² + 2x – 168 = 0. x = 12, x = -14. Numbers: 12, 14 or -14, -12.
Formula Used: Factorization
Q46 (Asked in 2024):
Solve x² – 10x + 25 = 0 by factorization.
Solution: x² – 10x + 25 = (x – 5)² = 0. Root: x = 5.
Formula Used: Factorization
Q47 (Asked in 2023):
Solve 3x² – 2x – 5 = 0 by quadratic formula.
Solution: a = 3, b = -2, c = -5. D = 4 + 60 = 64. x = [2 ± 8]/6. x = 5/3, x = -1.
Formula Used: Quadratic Formula
Q48 (Asked in 2022):
Find the discriminant of 2x² – 4x + 3 = 0.
Solution: D = (-4)² – 4(2)(3) = 16 – 24 = -8. No real roots.
Formula Used: Discriminant
Q49 (Asked in 2021):
Solve x² + x – 12 = 0 by factorization.
Solution: x² + x – 12 = (x + 4)(x – 3) = 0. Roots: x = -4, x = 3.
Formula Used: Factorization
Q50 (Asked in 2020):
A rectangle’s length is 2 cm more than its width, and its area is 120 cm². Find the dimensions.
Solution: Let width = x. Length = x + 2. x(x + 2) = 120. x² + 2x – 120 = 0. x = 10, x = -12. Width = 10 cm, length = 12 cm.
Formula Used: Factorization
Q51 (Asked in 2019):
Solve 2x² + x – 3 = 0 by completing the square.
Solution: Divide by 2: x² + x/2 = 3/2. Add (1/4)² = 1/16: (x + 1/4)² = 25/16. x = 1, x = -3/2.
Formula Used: Completing the Square
Q52 (Asked in 2018):
Solve x² – 3x – 4 = 0 by factorization.
Solution: x² – 3x – 4 = (x – 4)(x + 1) = 0. Roots: x = 4, x = -1.
Formula Used: Factorization
Q53 (Asked in 2017):
Find the nature of roots of x² + 3x + 3 = 0.
Solution: D = 3² – 4(1)(3) = 9 – 12 = -3. No real roots.
Formula Used: Discriminant
Q54 (Asked in 2016):
Solve 2x² – 5x + 3 = 0 by quadratic formula.
Solution: a = 2, b = -5, c = 3. D = 25 – 24 = 1. x = [5 ± 1]/4. x = 3/2, x = 1.
Formula Used: Quadratic Formula
Q55 (Asked in 2015):
The product of two consecutive numbers is 156. Find the numbers.
Solution: x(x + 1) = 156. x² + x – 156 = 0. Factorize: (x + 13)(x – 12) = 0. x = 12. Numbers: 12, 13.
Formula Used: Factorization
Q56 (Asked in 2014):
Solve x² + 7x + 12 = 0 by factorization.
Solution: x² + 7x + 12 = (x + 4)(x + 3) = 0. Roots: x = -4, x = -3.
Formula Used: Factorization
Q57 (Asked in 2013):
Solve 3x² – x – 4 = 0 by quadratic formula.
Solution: a = 3, b = -1, c = -4. D = 1 + 48 = 49. x = [1 ± 7]/6. x = 4/3, x = -1.
Formula Used: Quadratic Formula
Q58 (Asked in 2012):
Find the discriminant of x² – 10x + 25 = 0.
Solution: D = (-10)² – 4(1)(25) = 100 – 100 = 0. Equal real roots.
Formula Used: Discriminant
Q59 (Asked in 2011):
Solve x² – 5x + 6 = 0 by completing the square.
Solution: x² – 5x = -6. Add (5/2)² = 25/4: (x – 5/2)² = 1/4. x = 3, x = 2.
Formula Used: Completing the Square
Q60 (Asked in 2010):
The area of a rectangle is 96 cm², and its length is 4 cm more than its width. Find the dimensions.
Solution: Let width = x. Length = x + 4. x(x + 4) = 96. x² + 4x – 96 = 0. x = 8, x = -12. Width = 8 cm, length = 12 cm.
Formula Used: Factorization
Q61 (Asked in 2024):
Solve x² – 4x – 12 = 0 by factorization.
Solution: x² – 4x – 12 = (x – 6)(x + 2) = 0. Roots: x = 6, x = -2.
Formula Used: Factorization
Q62 (Asked in 2023):
Solve 2x² + 7x + 6 = 0 by quadratic formula.
Solution: a = 2, b = 7, c = 6. D = 49 – 48 = 1. x = [-7 ± 1]/4. x = -3/2, x = -2.
Formula Used: Quadratic Formula
Q63 (Asked in 2022):
Find the nature of roots of x² + 5x + 7 = 0.
Solution: D = 5² – 4(1)(7) = 25 – 28 = -3. No real roots.
Formula Used: Discriminant
Q64 (Asked in 2021):
Solve x² + 2x – 15 = 0 by factorization.
Solution: x² + 2x – 15 = (x + 5)(x – 3) = 0. Roots: x = -5, x = 3.
Formula Used: Factorization
Q65 (Asked in 2020):
The sum of a number and its reciprocal is 17/4. Find the number.
Solution: x + 1/x = 17/4. x² + 1 = 17x/4. 4x² – 17x + 4 = 0. x = 4, x = 1/4.
Formula Used: Quadratic Formula
Q66 (Asked in 2019):
Solve 3x² + 4x – 4 = 0 by completing the square.
Solution: Divide by 3: x² + 4/3x = 4/3. Add (2/3)² = 4/9: (x + 2/3)² = 16/9. x = 2/3, x = -2.
Formula Used: Completing the Square
Q67 (Asked in 2018):
Solve x² – 9x + 18 = 0 by factorization.
Solution: x² – 9x + 18 = (x – 3)(x – 6) = 0. Roots: x = 3, x = 6.
Formula Used: Factorization
Q68 (Asked in 2017):
Find the discriminant of 2x² – 3x + 2 = 0.
Solution: D = (-3)² – 4(2)(2) = 9 – 16 = -7. No real roots.
Formula Used: Discriminant
Q69 (Asked in 2016):
Solve 2x² – x – 1 = 0 by quadratic formula.
Solution: a = 2, b = -1, c = -1. D = 1 + 8 = 9. x = [1 ± 3]/4. x = 1, x = -1/2.
Formula Used: Quadratic Formula
Q70 (Asked in 2015):
The product of two consecutive even numbers is 624. Find the numbers.
Solution: x(x + 2) = 624. x² + 2x – 624 = 0. Factorize: (x + 26)(x – 24) = 0. x = 24. Numbers: 24, 26.
Formula Used: Factorization
Q71 (Asked in 2014):
Solve x² + 8x + 15 = 0 by factorization.
Solution: x² + 8x + 15 = (x + 5)(x + 3) = 0. Roots: x = -5, x = -3.
Formula Used: Factorization
Q72 (Asked in 2013):
Solve 3x² + 2x – 8 = 0 by quadratic formula.
Solution: a = 3, b = 2, c = -8. D = 4 + 96 = 100. x = [-2 ± 10]/6. x = 4/3, x = -2.
Formula Used: Quadratic Formula
Q73 (Asked in 2012):
Find the nature of roots of x² – 12x + 36 = 0.
Solution: D = (-12)² – 4(1)(36) = 144 – 144 = 0. Equal real roots.
Formula Used: Discriminant
Q74 (Asked in 2011):
Solve x² – 3x – 10 = 0 by completing the square.
Solution: x² – 3x = 10. Add (3/2)² = 9/4: (x – 3/2)² = 49/4. x = 5, x = -2.
Formula Used: Completing the Square
Q75 (Asked in 2010):
The sum of squares of two consecutive numbers is 265. Find the numbers.
Solution: x² + (x + 1)² = 265. 2x² + 2x + 1 = 265. x² + x – 132 = 0. x = 11, x = -12. Numbers: 11, 12 or -12, -11.
Formula Used: Factorization
Q76 (Asked in 2024):
Solve x² – 7x + 10 = 0 by factorization.
Solution: x² – 7x + 10 = (x – 2)(x – 5) = 0. Roots: x = 2, x = 5.
Formula Used: Factorization
Q77 (Asked in 2023):
Solve 2x² + 4x – 6 = 0 by quadratic formula.
Solution: a = 2, b = 4, c = -6. D = 16 + 48 = 64. x = [-4 ± 8]/4. x = 1, x = -3.
Formula Used: Quadratic Formula
Q78 (Asked in 2022):
Find the discriminant of x² + 4x + 5 = 0.
Solution: D = 4² – 4(1)(5) = 16 – 20 = -4. No real roots.
Formula Used: Discriminant
Q79 (Asked in 2021):
Solve x² + 4x – 5 = 0 by factorization.
Solution: x² + 4x – 5 = (x + 5)(x – 1) = 0. Roots: x = -5, x = 1.
Formula Used: Factorization
Q80 (Asked in 2020):
A train travels 300 km at a uniform speed. If the speed had been 10 km/h more, it would have taken 1 hour less. Find the speed.
Solution: Let speed = x km/h. 300/x – 300/(x + 10) = 1. x² + 10x – 3000 = 0. x = 50. Speed: 50 km/h.
Formula Used: Quadratic Formula
Q81 (Asked in 2019):
Solve 2x² – 3x – 5 = 0 by completing the square.
Solution: Divide by 2: x² – 3/2x = 5/2. Add (3/4)² = 9/16: (x – 3/4)² = 49/16. x = 5/2, x = -1.
Formula Used: Completing the Square
Q82 (Asked in 2018):
Solve x² – 6x + 8 = 0 by factorization.
Solution: x² – 6x + 8 = (x – 4)(x – 2) = 0. Roots: x = 4, x = 2.
Formula Used: Factorization
Q83 (Asked in 2017):
Find the discriminant of x² + 2x + 2 = 0.
Solution: D = 2² – 4(1)(2) = 4 – 8 = -4. No real roots.
Formula Used: Discriminant
Q84 (Asked in 2016):
Solve 3x² – 5x – 2 = 0 by quadratic formula.
Solution: a = 3, b = -5, c = -2. D = 25 + 24 = 49. x = [5 ± 7]/6. x = 2, x = -1/3.
Formula Used: Quadratic Formula
Q85 (Asked in 2015):
The product of two consecutive odd numbers is 399. Find the numbers.
Solution: x(x + 2) = 399. x² + 2x – 399 = 0. Factorize: (x + 21)(x – 19) = 0. x = 19. Numbers: 19, 21.
Formula Used: Factorization
Q86 (Asked in 2014):
Solve x² + 3x – 4 = 0 by factorization.
Solution: x² + 3x – 4 = (x + 4)(x – 1) = 0. Roots: x = -4, x = 1.
Formula Used: Factorization
Q87 (Asked in 2013):
Solve 2x² + x – 4 = 0 by quadratic formula.
Solution: a = 2, b = 1, c = -4. D = 1 + 32 = 33. x = [-1 ± √33]/4.
Formula Used: Quadratic Formula
Q88 (Asked in 2012):
Find the nature of roots of x² – 4x + 5 = 0.
Solution: D = (-4)² – 4(1)(5) = 16 – 20 = -4. No real roots.
Formula Used: Discriminant
Q89 (Asked in 2011):
Solve x² – x – 12 = 0 by completing the square.
Solution: x² – x = 12. Add (1/2)² = 1/4: (x – 1/2)² = 49/4. x = 4, x = -3.
Formula Used: Completing the Square
Q90 (Asked in 2010):
The area of a rectangle is 80 cm², and its length is 6 cm more than its width. Find the dimensions.
Solution: Let width = x. Length = x + 6. x(x + 6) = 80. x² + 6x – 80 = 0. x = 8, x = -10. Width = 8 cm, length = 14 cm.
Formula Used: Factorization
Q91 (Asked in 2024):
Solve x² – 8x + 12 = 0 by factorization.
Solution: x² – 8x + 12 = (x – 6)(x – 2) = 0. Roots: x = 6, x = 2.
Formula Used: Factorization
Q92 (Asked in 2023):
Solve 2x² – 5x – 3 = 0 by quadratic formula.
Solution: a = 2, b = -5, c = -3. D = 25 + 24 = 49. x = [5 ± 7]/4. x = 3, x = -1/2.
Formula Used: Quadratic Formula
Q93 (Asked in 2022):
Find the nature of roots of x² + 6x + 10 = 0.
Solution: D = 6² – 4(1)(10) = 36 – 40 = -4. No real roots.
Formula Used: Discriminant
Q94 (Asked in 2021):
Solve x² + 5x – 6 = 0 by factorization.
Solution: x² + 5x – 6 = (x + 6)(x – 1) = 0. Roots: x = -6, x = 1.
Formula Used: Factorization
Q95 (Asked in 2020):
The sum of a number and its reciprocal is 13/6. Find the number.
Solution: x + 1/x = 13/6. 6x² – 13x + 6 = 0. x = 3/2, x = 2/3.
Formula Used: Quadratic Formula
Q96 (Asked in 2019):
Solve 2x² + x – 1 = 0 by completing the square.
Solution: Divide by 2: x² + x/2 = 1/2. Add (1/4)² = 1/16: (x + 1/4)² = 9/16. x = 1/2, x = -1.
Formula Used: Completing the Square
Q97 (Asked in 2018):
Solve x² – 7x + 12 = 0 by factorization.
Solution: x² – 7x + 12 = (x – 3)(x – 4) = 0. Roots: x = 3, x = 4.
Formula Used: Factorization
Q98 (Asked in 2017):
Find the discriminant of x² – 2x + 3 = 0.
Solution: D = (-2)² – 4(1)(3) = 4 – 12 = -8. No real roots.
Formula Used: Discriminant

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मुझे गणित पढ़ाने का 7 वर्षों का अनुभव है। मैंने हजारों छात्रों को बोर्ड परीक्षाओं और प्रतियोगी परीक्षाओं की तैयारी में मार्गदर्शन दिया है। मेरी खासियत है – गणित को आसान भाषा और रोचक तरीके से समझाना।
वेबसाइट के बारे में
MadhyamikPariksha.com एक निजी शैक्षिक पोर्टल है, जहाँ छात्र हिंदी माध्यम में पढ़ाई से जुड़ी उपयोगी सामग्री पा सकते हैं। यहां उपलब्ध हैं:
माध्यमिक और उच्च माध्यमिक परीक्षाओं की तैयारी सामग्री
2. पुराने प्रश्न पत्र और हल
3.गणित क्विज़, मॉक टेस्ट, और अपडेट्स
सरकारी पोर्टल नहीं है
स्पष्टीकरण: यह वेबसाइट सरकारी पोर्टल नहीं है। इसका किसी भी सरकारी विभाग, बोर्ड या संस्था से कोई संबंध नहीं है। यह एक निजी प्रयास है, जिसका मकसद छात्रों को मदद पहुंचाना है।
हमारा उद्देश्य
हमारा लक्ष्य है कि हर छात्र को पढ़ाई में मार्गदर्शन मिले, चाहे वह बोर्ड परीक्षा की तैयारी कर रहा हो या प्रतियोगी परीक्षा की। हम विषयों को आसान भाषा में, बिना डर के समझाने में यकीन रखते हैं।
अगर आपको कोई सुझाव या प्रश्न हो, तो आप संपर्क करें पेज के माध्यम से मुझसे जुड़ सकते हैं।
चंद्रशेखर
(M.Sc Maths, B. Sc, B.Ed, TGT Qualified 2016, UPTET Qualified)